bindcontact

Question

سلام

من میخوام تو متد bindContact اطلاعات را بگیرم ولی الان نمیدونم چطوری آرایه رو وارد کنم ، بدون bindContact کار میکنه و از Position استفاده می کنم ولی الان تو bindContact گیر کردم.

ممنون.

public class ListContactAdapter extends ArrayAdapter {
     String []name ;
     String [] familyName ;
     int [] proilePics ;
     Context context ;
     LayoutInflater inflater ;

    public ListContactAdapter(@NonNull Context context,  String[] name, String[] familyName, int[] proilePics) {
        super(context, R.layout.mylayout,name);
        this.name = name;
        this.familyName = familyName;
        this.proilePics = proilePics;
        this.context = context;

    }

    @NonNull
    @Override
    public View getView(int position, @Nullable View convertView, @NonNull ViewGroup parent) {
        //inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        View row = convertView ;
        ViewHolder viewHolder = null ;
        if (row== null) {
            row = LayoutInflater.from(parent.getContext()).inflate(R.layout.mylayout, parent, false);
            row.setTag(viewHolder);
            viewHolder = new ViewHolder(row);
        }
        else
        {
           viewHolder = (ViewHolder) row.getTag();
        }

        viewHolder.bindContact(proilePics[position],name[position],familyName[position]);
        //viewHolder.imageView.setImageResource(proilePics[position]);
       // viewHolder.fName.setText(name[position]);
       // viewHolder.myName.setText(familyName[position]);

        return row ;
    }

    class ViewHolder extends RecyclerView.ViewHolder {
        ImageView imageView  ;
        TextView myName ;
        TextView fName;
        public ViewHolder(@NonNull View row) {
            super(row);
           imageView = row.findViewById(R.id.profile_pic) ;
            myName = row.findViewById(R.id.name);
             fName = row.findViewById(R.id.family_name);

        }

        public  void bindContact(String [] name , String fname , int images)
        {

            imageView.setImageResource(images);
            myName.setText(name());
            fName.setText(fname);

        }
    }
}

اندروید

Reza Tavassoli

10 فروردین 99

Answer 1

حذف شده

public class ListContactAdapter extends ArrayAdapter<StructUser> {
    LayoutInflater inflater ;

    public ListContactAdapter (@NonNull Context context,  ArrayList<StructUser> users) {
        super(context, 0, users);
        inflater = LayoutInflater.from(context);
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        StructUser user = getItem(position);

        ViewHolder holder;
        if (convertView == null) {
            convertView = inflater.inflate(R.layout.mylayout, parent, false);

            holder = new ViewHolder();
            holder.imageView = (TextView) convertView.findViewById(R.id.profile_pic);
            holder.myName = (TextView) convertView.findViewById(R.id.name);
            holder.fName = (TextView) convertView.findViewById(R.id.family_name);

            convertView.setTag(holder);
        } else {
            holder = (ViewHolder) convertView.getTag();
        }

        holder.myName.setText(user.name);
        holder.fName.setText(user.fname);

        return convertView;
    }

    private static class ViewHolder {
        ImageView imageView;
        TextView myName;
        TextView fName;
    }

}

توسط

محسن موحد

10 فروردین 99

bindcontact

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